9v DC from 12v DC?? |
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Shortrope
Young Croc Joined: 08 July 2013 Location: Ireland Status: Offline Points: 1232 |
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Posted: 08 August 2014 at 5:52pm |
Hey hey...
I've got a couple of digital Voltage readouts I bought a while back. On reading the small print I've stupidly got ones that require a 9v dc power supply. Pain in the hole!! Is there a simple way of stepping down the 12v supply 9v? |
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My Tinnitus is coming along nicely!!
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audiomik
Old Croc Joined: 06 April 2010 Location: Bath, UK Status: Offline Points: 2962 |
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you could use an LM7809 voltage regulator IC.
Datasheet and application notes: http://www.datasheetcatalog.com/datasheets_pdf/L/M/7/8/LM7809.shtml Mik |
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mini-mad
Old Croc Joined: 13 July 2012 Location: london Status: Offline Points: 6903 |
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+1... thats the smae way i would do it. |
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If it sounds like a gorilla is trying to escape, turn it down.
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Shortrope
Young Croc Joined: 08 July 2013 Location: Ireland Status: Offline Points: 1232 |
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Ta very much!....as you were!
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My Tinnitus is coming along nicely!!
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bitSmasher
Old Croc Joined: 23 June 2012 Location: Melbourne Status: Offline Points: 2295 |
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I read somewhere on here the voltmeter supply should be isolated from the battery it's measuring - what effect does this have on readout?
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odc04r
Old Croc Joined: 12 July 2006 Location: Sarfampton Status: Offline Points: 5482 |
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Only reason I could think of for that is if the voltmeter needed a reference voltage and you wanted it to be different from the voltage rail that was supplying it power. Say you want to monitor a 12V battery voltage and that was also the supply to the meter, as the 12V voltage dropped your measurement reference would shift and your reading would be wrong.
So to avoid this you could use another battery for the meter power that would keep a charge for much longer than your main battery because it was supplying a very small current to the meter displays only. Another would be to use a regulator to drop your main supply to about half it's value and then use a double or triple voltage ladder circuit to bump it high enough to power the meter. it more work involved in this one but as the battery voltage drops from it's initial value the regulator will keep it's output constant. You'd design so at the regulator output + its dropped voltage would be lower then the minimum supply for your boombox. There may be other ways too, I might be overthinking this! Edit - Ammeters often need a separate supply to avoid shorting depending on their design and if you use a shunt resistor or a current transformer. Edited by odc04r - 09 August 2014 at 11:10am |
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audiomik
Old Croc Joined: 06 April 2010 Location: Bath, UK Status: Offline Points: 2962 |
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Internal reference Voltage of DMMs are normally Band-Gap devices or similar so that Vs doesn't affect readings.
Yes about isolating Ammeters with resistive shunt resistors: since you can short between the + and - battery terminals if measuring the current in the positive leg of the same supply. Usual practice in the common supply situation for current measurement is to use a Hall Effect sensor for DC or an isolated Current Transformer for AC. Both of these isolate the meter input from the current being measured. hope this assists Mik |
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studio45
Old Croc Joined: 16 October 2007 Location: United Kingdom Status: Offline Points: 3864 |
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I bought a cheap meter module off eBay and it can work from either a 9v battery or the measured supply if it's under 15v, however the instructions are pretty Engrish and not very clear, so given the possibility of letting all the magic smoke out of the thing/ actually setting it on fire I opted for the 9v battery. Seems to work fine even off a partially used 9v that measures 7-8v and stays as accurate as ever it is.
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Studio45 - Repairs & Building Commotion Soundsystem -Mobile PA
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