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Question on ohms |
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Requiem
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Topic: Question on ohmsPosted: 26 January 2012 at 9:45pm |
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Hi, just a quick one...
can i put an 8 ohm driver in series with a 16 ohm driver, and does that amount to 6 ohms? also when amplifying, do i take halfway between the 8 ohm output and the 4 ohm output as a rough guide to what the amp will be putting out @ 6 ohms? or is it not as simple as that. im not too sure so just asking to clear it up... i have a pair of tops loaded with double 16ohm drivers and one got ripped apart by some idiot at a party in each top. i bought a pair of matching drivers to replace them with but they are slightly different, in nothing apart from the new ones are 8 ohm per driver and the other 2 working ones i will be coupling them with are 16ohm. any info would be appreciated , cheers
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djeddie
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Posted: 26 January 2012 at 10:17pm |
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It actually comes out as 5.333Ω. But you're right on roughly going halfway between the 4Ω and 8Ω rating.
The other thing to bear in mind is the 8Ω driver will have 2/3 of the power going to the cab with the 16Ω driver having the other 1/3. So with 300 watts to the cab, 200w will go through the 8Ω driver and 100w through the 16Ω driver in simple terms. |
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E=mc² ±3dB
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MessyM2k8
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Posted: 26 January 2012 at 10:37pm |
It'll be 16 + 8 which is 24ohms |
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MessyM2k8
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Posted: 26 January 2012 at 10:38pm |
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Requiem
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Posted: 26 January 2012 at 10:42pm |
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Ok, both drivers are 300w rms, so will i have problems getting the 16 ohm one to perform as well as it could without blowing the 8ohm one? is there any way i can avoid this by putting the 16 ohm driver first in the series or any other method?
seems to be a bit of a dilema, would i be better off putting both the 8 ohm drivers in one of the tops and both the 16 ohm drivers in the other one, bearing in mind they will both be going off the same amp, and turning up the side with the two 16 ohm drivers more? they are exactly the same drivers aside from the Ω
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Requiem
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Posted: 26 January 2012 at 10:45pm |
im pretty sure thats wrong.... because as i understand it 2 8Ω drivers make a 4Ω load, 3 make a 2.7Ω load and 4 8Ω make a 2Ω load correct me if im wrong anyone
Edited by Requiem - 26 January 2012 at 10:46pm |
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MessyM2k8
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Posted: 26 January 2012 at 10:49pm |
you say series do you mean parallel? |
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Requiem
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Posted: 26 January 2012 at 11:23pm |
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i mean as in going from the amp to one driver and then on to another driver...
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knet94
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Posted: 26 January 2012 at 11:35pm |
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Inside the cabinet if the drivers are wired with both positives wired together (from the amp) and both negatives wired together (going back to the amp) then this is paralell.
If the positive from the amp goes to the positive of one driver and then the negative is connected to the positive of the other driver and then the negative goes back to the amp this is a series. You need to know which one as it's fundamental to calculating ohmage when using multiple drivers. Hope that helps. |
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kedwardsleisure
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Posted: 27 January 2012 at 12:20am |
If you connect in parallel it is 5.33 ohms. If you connect in series it is 24 ohms I wouldn't do it either way unless uneven driving is your goal. Find another solution. Edited by kedwardsleisure - 27 January 2012 at 12:20am |
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K. Edwards Electronics Engineers
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MessyM2k8
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Posted: 27 January 2012 at 12:31am |
Your best way is to match the drivers in the cabs and wire them in parallel, so you put both the 16ohm drivers in one cab in parallel (8ohms) and the 8ohm drivers in parallel (4ohms) in the other cab. |
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GEB
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Posted: 27 January 2012 at 10:07am |
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Why is this in the 'advanced' section?
The best and easiest solution would be 4 matching drivers, eg; 8 ohms. Funds permitting of course. But then again, it probably won't be long before the 8 ohm drivers get too much power and blow anyway if they're matched with the 16 ohm drivers, costing you more in the long run!
Edited by GEB - 27 January 2012 at 10:08am |
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