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Using amp too ‘big’ for a speaker

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Young Croc
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    Posted: 04 September 2022 at 8:47pm
Is there a general rule to convert a reduction of gain, in dB to watts? 
For example, a driver is 200w rms, the amp is 1500w rms. With the amp gain knob set to 0dB, how much reduction in gain on the output of the dsp should be set to achieve a rough output of 1.5x (300w) the rms of the driver? 
I hope this makes sense.
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Post Options Post Options   Thanks (0) Thanks(0)   Quote Conanski Quote  Post ReplyReply Direct Link To This Post Posted: 05 September 2022 at 12:15am
The answer is 7dB below whatever signal level drives the amp to full output. The math formula is DB = 10 log (P2/P1) or 10 log (300/1500) in this case.

A couple quick reference points...
A 3dB change equals a doubling/halfing of power, so for example -3dB from 1500w = 750w.
A 10dB change equals a 10 fold change in power, so -10dB from 1500w = 150w.
So with that you know the answer is between -3dB and -10dB but closer to -10dB
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Post Options Post Options   Thanks (0) Thanks(0)   Quote Earplug Quote  Post ReplyReply Direct Link To This Post Posted: 05 September 2022 at 7:06am
Also, note that if the gain control on the amp is logarithmic and marked from 1 - 10 (which is the norm) dropping from 10 to 8 will do it as well - as long as you limit the input to the amp to it's nominal level for maximum output, i.e. don't overdrive it to compensate!  Smile
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Post Options Post Options   Thanks (0) Thanks(0)   Quote toastyghost Quote  Post ReplyReply Direct Link To This Post Posted: 07 September 2022 at 3:41am
Be aware that you’ll still be able to push the full output of the amplifier to the driver if you just turn the pot on the front down. It will just take more voltage at the amplifier input terminal to achieve it because all the pot does is adjust the input sensitivity.
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Post Options Post Options   Thanks (0) Thanks(0)   Quote VECTORDJ Quote  Post ReplyReply Direct Link To This Post Posted: 08 September 2022 at 10:08pm
VECTORSONICS for Recones in Auburn, Maine USA........ 
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