Halving number of drivers = ...?
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Category: General
Forum Name: Newbie Discussion
Forum Description: Newbie Discussion/Questions. Look less stupid here...
URL: https://forum.speakerplans.com/forum_posts.asp?TID=108815
Printed Date: 26 March 2026 at 6:54pm
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Topic: Halving number of drivers = ...?
Posted By: teeth
Subject: Halving number of drivers = ...?
Date Posted: 28 November 2024 at 3:44pm
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i have a small reflex box here, dual 8" https://eaw.com/wp-content/uploads/2021/01/UB82.pdf" rel="nofollow - https://eaw.com/wp-content/uploads/2021/01/UB82.pdf don't think it's possible to find another driver for it. it's a nice sounding speaker, so don't want to bin it. for a fun project with my boy i'd like to rehouse this in a new box, and get a nice gentle day of woodworking in. i don't want to redesign anything this time. i'm actually not sure of the relationship between number of drivers and the resulting speaker. is it purely an efficiency / gain thing? so were i to redesign the box, i should keep the same ports / volume? cheers :) |
Replies:
Posted By: Earplug
Date Posted: 28 November 2024 at 4:56pm
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Why do you think that finding another suitable driver would be difficult? It should not be difficult to find something suitable. Personally, I'd go for something from P-Audio, that I've found to be a very reliable - and efficient brand, but if not, there must be something from B&C - or even Eminence that would do. ------------- Earplugs Are For Wimps! |
Posted By: teeth
Date Posted: 28 November 2024 at 5:20pm
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for sure, i guess it's just cheaper to buy a sheet of ply than 2x drivers. i also just fancy the project more :)
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Posted By: Tinnitus Rex
Date Posted: 28 November 2024 at 5:30pm
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The Crossover will act differently if it does not have the same impedance that was attached to its LF section ..this will only affect the LF but the hf might appear louder in relation to the LF . if it sounds ok to you now.. then its fine . ------------- "couldn't we just like... use headphones?" |
Posted By: Earplug
Date Posted: 28 November 2024 at 5:35pm
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"for sure, i guess it's just cheaper to buy a sheet of ply than 2x drivers." Both drivers are blown? I understood just one. Another alternative would be to stick in a passive radiator. That would be the cheapest!  ------------- Earplugs Are For Wimps! |
Posted By: teeth
Date Posted: 28 November 2024 at 7:44pm
i mean i know nothing about the driver in there so probably would replace both if i took that route
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Earplug wrote:Posted By: Earplug
Date Posted: 29 November 2024 at 9:06am
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Ok. Why not post a couple of photos and see if anyone here can't identify them?  ------------- Earplugs Are For Wimps! |
Posted By: teeth
Date Posted: 29 November 2024 at 10:56am
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i would quite like to do my project instead i think :) |
Posted By: Earplug
Date Posted: 29 November 2024 at 11:40am
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Haha, ok. Father & son week... ------------- Earplugs Are For Wimps! |
Posted By: Conanski
Date Posted: 29 November 2024 at 3:09pm
1/2 the number of drivers requires a cabinet with roughly 1/2 the internal volume, but ports and the passive crossover will be different so some calculations need to be made there.
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Posted By: teeth
Date Posted: 06 January 2026 at 9:09am
| was going to ask this question again, then remembered i made this post! |
Posted By: teeth
Date Posted: 06 January 2026 at 9:10am
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@Conanski just wondering, is there a relationship between the port size as well, can that bbe halved too?
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Posted By: Jan-2T
Date Posted: 06 January 2026 at 12:01pm
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In a perfect world without losses, half the amount of drivers need half the cab volume with half port volume. However the port wall losses will dictate a slightly different port volume is needed. Unless you're lucky and the original box had two ports, or a divided port, than you can easily reduce it to one. ------------- Music! |
Posted By: teeth
Date Posted: 06 January 2026 at 12:46pm
| Thank you @Jan-2T that is exactly the info i was hoping for. |