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This thread is a recap and discussion forum about the effects of capacitors in series with a driver. From my topic about my new build tops, several members got into a discussion about these effects, when a capacitor is not used for the crossover itself but instead for i.e. DC blocking. Please provide your opinion, measurements and whatnot so that hopefully we can not only clarify this for now, but also enlarge the knowledge available to the great community that speakerplans is.
I have reserverd the first 4 posts for measurements. This way we can append detailed measurement (series), or theoretical approximations, models etc. to the front page, making the topic more clear. Please contact me via this topic or PM to append certain text or images to these first posts.
RC Circuit Theory basics
An RC circuit is an electrical filter circuit composed of an electric resistance R and a capacitance C. The total impedance of this circuit is a complex system, in the name that it has a real resistive part Zreal = R and imaginary capactive part Zcomplex= 1/((k+iw)*C). Here - k is the Exponential decay constant, generally assumed zero for a perfect sinusoid. We now call the quantity iw equal to s for ease of writing.
- i is the complex unit, where i^2=-1
- w is the angular frequency in radians/second.
The special quality a capacitor has (in series with a resistor) is that the current through the capacitor is equal to a constant multiplied by the change in the voltage, or mathmatically Basically this equation states that the current through the capacitor (left hand side) is equal to the current through the resistor (right hand side). Off course in a closed circuit lacking a current or voltage source, the currents have to be equal and of opposite sign as any current will be dissipated through the resistance.
This equation is basically a first order differential equation, because it states that a change in voltage over time multiplied by a constant is equal to the voltage itself. We can solve this equation for the voltage with the knowledge that the only equation satisfying this condition is an exponential decay function, where the behavior of the decay is controlled by the multiplication factor. Rewriting the equation we get: Integrating the left and right side we get Where B is an arbitrary constant. Rewriting again by taking the exponent left and right we get When we call Exp(B) the voltage V0 across the capacitor at time t=0, we get the voltage Although this is purely mathmetical, we can see something very important. This is that it takes time for a capacitor to react to a certain voltage applied to it. This reaction is controlled completely by the constant RC, the decay constant. When the value of RC is large, the voltage over the capacitor will stabilise slower than when the RC constant is lower.
To explain why a capacitor in series with a resistor can act like a high-pass filter, we can look at the transfer function, the comparison between the voltage applied across the RC circuit, and the voltage actually presented to the resistor. ---To be updated.
Without further mathmatical reroute's, it can be found on wikipedia anyway... (link below) http://en.wikipedia.org/wiki/RC_circuit" rel="nofollow - http://en.wikipedia.org/wiki/RC_circuit The transfer function of the RC circuit over the reistor is again a complex value. It equals: Hr(s)=RCs/(1+RCs) where s again is equal to iw.
We can plot the transfer function of this system in a frequency-gain window and a frequency-phase window. This is generally called a BODE plot. it always has a characteristic shape as shown below. What we can see from this is that a simple RC circuit gives a -6dB/octave decay in the frequency domain, and a phase twist of maximally 90 degrees at frequency zero. The phase shift is always 45 degrees at the -3dB point of the filter, also known as the knee point or F3.
We can do a similar analysis for a low pass network where the capacitor is switched out for an inductor ( a coil) as well as for higher order filter networks. The basics may however (hopefully) be clear.
As the frequency increases, the relative impedance of the capacitor compared to the resistor decreases and the effects the capacitor has on the signal become small. The phase shift of the filter is said to asymptotically approach zero as the frequency goes to infinity, however the differences become rather small pretty quickly in practice.
The entire signal however is still passing through the capacitor, even though the ''measurable differences are small in in practice.
The contradiction. For many years, it has been known that different capacitors give slighly different representations of sound. Qualitative measurements about the differences in how a capacitor handles ripple current, equivalent series resitance of a capacitor, memory effects have all been researched. Most effects however only become noticeable when the frequency of a sinoid becomes way higher than any audio loudspeaker will ever be able to reproduce.
The discussion came to live when i could not hear a clear difference between having a series capacitor in place, whilst others reported the contrary. After several measurements, which will be included below, i came to my own conclusion that there is no (noticeable) effect a capacitor has on the sound quality.
From a theoretical point of view, it is however completely frustrating and bonkers that we can not comprehend to explain which quantity would be responsible for the (significant) audible difference in sound quality. Hence the case for this discussion: What is it, that makes the sound quality deteriorate, especially when using larger capacitors??
------------- Best regards, Teun.
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