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HD15 Hornresp modellling |
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ceharden
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Topic: HD15 Hornresp modelllingPosted: 06 June 2005 at 8:05pm |
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Hopefully a quick question for someone please:
I'm trying to model the HD15 in Hornresp to tweak the size of the box, I want to make it the same size as some 18" reflex boxes I use for ease of stacking. The problem I have is deciding what type of horn flare to model it as. It looks much more rapid than most horn flares, even taking into account all the flare is on one side. I'm guessing someone else has done this already, so if you could let me know what parameters you used please I'd be grateful. Thanks. |
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Timber_MG
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Posted: 07 June 2005 at 2:50am |
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Don't forget to add the large front chamber and a little extra length
for end-factor correction. Tb_mike posted a link to an article
(audioroundtable high-eficiency methinks) dissecting the original
Turbosound analytically which said basically 70Hz loading, though
practice tells one that in larger stacks(8-12) (you should really use
at a very least 4 when expecting any much bass) you can expect
something to about 50ish.
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ceharden
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Posted: 07 June 2005 at 6:14am |
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As I can't work out how to model the flare as a single curve, I've been
trying to use multiple conical segments as that's how I'll probably
construct it. Sticking with the original measurements for now I'm
getting CIR > 1 warnings for my final flare segment because of the
speed of expansion. Will this actually affect my simulation
results significantly?
I think I've got all the dimensions right (Including large throat and rear chambers) but the results don't quite seem right, eg the diaphragm displacement is quite large even within the horn passband (2mm @ 150Hz, 1W input). If anyone has modelled the HD15 in Hornresp and can do a screenshot of the input params please it would save me a lot of frustration. Thanks in advance. |
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fernand
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Joined: 06 January 2005 Location: Belgium Status: Offline Points: 24 |
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Posted: 08 June 2005 at 9:44am |
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I have the same question. It might be a good idea to open a thread in the general forum that is reserved for box models. It appears to me that a lot of people try to model the boxes of the plans to see whatever result they could have with a specific speaker. That way, we could avoid to do the same things again and again. Anyone has available model parameters (hornresp, winisd, ...) |
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tb_mike
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Joined: 01 October 2004 Location: New Zealand Status: Offline Points: 2744 |
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Posted: 10 June 2005 at 12:34am |
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Post us your input screenshot and wel see whats wrong. I modeled an exponential approximation of it,and it looked similar to the HD15Plot. Ensure driver parameters are inputted in the right order,ensure cubic centimetres or litres inputted..etc Note that on finite horns the loading differences arent so apparent. With one box in 2pi space the excursion can still be high,the horn is too small to support the long wavelengths. Try modeling an infinite hornor HYPEX horn and compare the acoustic impedence and excursion plot etc to realistic horns. Edited by tb_mike |
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ceharden
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Posted: 11 June 2005 at 6:44am |
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Here is my attempt at the HD15 simulation params. Response
doesn't quite match Rog's on the HD15 page but it seems sensible.
![]() ![]() If you could tell me if I'm going along the right lines please. As you say, the flare type doesn't make a great deal of difference. The only other bit I'm not sure about is the throat chamber i.e. what to choose for the area given the throat is not on the same axis as the driver. Cheers... |
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Dave Slater
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Posted: 06 August 2005 at 5:57am |
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the axis of the throat doesn't matter it's just the smallest area the air has to travel through in the case of the HD15 the throat area is 544.8cm^2 the front chamber is any space between this and the driver including the volume of air contained within the cone itself on the HD15 the easiest way to figure this out is to use pythagoras' theorum to work out the area of the triangle ie. you know the size of the baffle 42cm and the distance away from the back panel at the top of it is 20cm assuming a right angled triangle the sq root of 42^2 - 20^2 gives 36.9cm or the height up the back panel 20*36.9=738 divide that by 2 and you have the area of that triangle or 369cm^2 multiply that by 47.2 and you have 17416.8cm^3 or 17.4 litres add on 2.5l for the volume of the cone and a rough guess of 20litres for the front chamber would be about right |
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Timber_MG
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Posted: 12 August 2005 at 2:24am |
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That sim also comes fairly close at the low end to the measured response.
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ceharden
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Posted: 12 August 2005 at 12:45pm |
Cheers, good to know I managed to get the sim somewhere near right. Been playing with some variations on the original HD15, slightly deeper cabinet for a longer path etc. |
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Jimbo
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Posted: 12 August 2005 at 1:19pm |
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I may be wrong, (and if I am, Please tell me so!) but shouldn't that plot be made at 2 x pi? (1 on the floor?) If I'm wrong about this, I've been modeling a new design all wrong. Jim |
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ceharden
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Posted: 12 August 2005 at 1:44pm |
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I'm not exactly sure, but I think 1xpi is appropriate if you use
multiple cabinets together (one HD15 wouldn't be very useful).
For modelling most situations you are right about using 2xpi.
Anyone else care to correct? |
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Jimbo
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Posted: 12 August 2005 at 3:46pm |
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I just checked the plan and it's listed as quarter space as well. The comment about Rog's plot not matching is more what spurred the question, but any other comments would still be appriciated. Thanks Jim |
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